Question

plz solve this question fast need help​

Answer 1

Answer:

theta is zero as given it is horizontal

range is 10 m

V²/g=10

V=10(if started from ground)

given,

i.e asked velocity at height 1.25m

v²/2g is maximum height formula

h=v²/2g(sin 2theta =1 , as theta =0)

h=1.25m

v=√2gh

v=2×10×1.25

v=25 (if started from height 1.25m from ground)

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