plz solve this question .....Find the value of p(1/2)for p(X)=x^4-x^2+X....... please...
Attachments:
Answers
Answered by
5
p(1/2)=(1/2)^4-(1/2)^2+1/2
=1/16-1/4+1/2
=1-4+8/16
=5/16
=1/16-1/4+1/2
=1-4+8/16
=5/16
vicky009:
do you have whatsapp
if yes take my number
yes
8700590977
7404220710
message me
i had messaged you on whatsapp check
Why are you continuously sending messages me
i am messaging karn89
sorry for disturbing
Answered by
3
p(X) = p(1/2)
(1/2)^4 - (1/2)^2 + 1/2
1/16 - 1/4 + 1/2
-3/16 + 1/2
5/16
This is the solution of your question. I hope that it will help you.
(1/2)^4 - (1/2)^2 + 1/2
1/16 - 1/4 + 1/2
-3/16 + 1/2
5/16
This is the solution of your question. I hope that it will help you.
hi
thanks a lot for solving
whom do i mark brainleist
Welcome
i need more help will you help me
Yes
do you have whatsapp take my number
No
Similar questions