Math, asked by sambitsambit135, 1 year ago

Derivative of the function cosec(ax+b)^2

Answers

Answered by praneethks
8
the derivative of
 { \csc(ax + b) }^{2}
is 2 cosec(ax+b)d/dx(cosec(ax+b))= -2a(cosec(ax+b)^2 )cot(ax+b)
Answered by charancj
16
d/dx(cosec(ax+b))²
= 2cosec(ax+b).(-cosec(ax+b)cot(ax+b)).a
=-2acosec(ax+b)²cot(ax+b)
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