Question

5g of ice at 0℃ and 20g of water at 45℃ are mixed the temperature of the mixture is

Answer 1

first 5gms of ice converts into 5gms of water requiring 400 cal of heat hence 400+5(1)t=20(1)(45-t) the resultant temperature be t . hence on solving we get 25t=500 therefore resultant temperature is 20 degree Celsius