plz solve this question for m its very urgent ..
if don't know plz stay away and plz do it step by step ..
best answer will mark as brainlist ... plz someone help m
Answers
Answer:
The perimeter of the rhombus will be 8root7 metres
Step-by-step explanation:
The rhombus consists of 4 sides that are equal in length.
It also has 4 right angles.
the diagonals are always into two equal parts .
In this rhombus, the lengths of diagonals are 16cm and 12 cm,
Therefore, the lengths of the height and adjacent sides are 8cm and 6cm respectively.
Now, we have to find the hypotenuse.
The hypotenuse will be root of 8^2 +6^2 = 2root 7
We know that the 4 sides are equal in length . therefore, the perimeter will be 2 root7 * 4 = 8 root 7 metres.
HOPE THIS HELPS YOU...
Answer:
here is your answer
Step-by-step explanation:
let AD and BC be the diagonals of the rhombus ABCD, and they intersect at O
BC=16 cm
AD=12 cm
all sides of a rhombus are equal, AB = BC = CD = AC
Also, diagonals of a rhombus bisect each other at 90°
⇒ AO = OD = 6 cm
⇒ BO = OC = 8 cm
consider ΔAOC,
∠AOC = 90° ( AD and BC bisect each other at right angles)
By Pythagoras theorem,
AC² = AO² + OC²
AC² = 6² + 8²
AC² = 36 + 64
AC = √100
AC = 10 cm
As AB = BC = CD = AC = 10 cm
⇒ perimeter = sum of all sides
⇒ P = 4a
P = 4(10)
∴ P = 40 cm
hope this helps you!!!
Pls mark my answer as the brainliest one as i spent a lot of time typing this answer