Question

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Answer 1

mode of the above given frequency distribution table is 10.

Answer 2

Answer:

$Mode=36$

Step-by-step explanation:

$f0 = 10, \: f1=16, \: f2 = 12, \: l=30, \: h=40-30=10$

$Mode = l + \frac{f1-f0}{2f1-f0-f2} \times h$

$Mode= 30 + \frac{16 - 10}{2(16) - 10 - 12} \times 10$

$Mode = 30 + \frac{16 - 10}{32 - 10 - 12} \times 10$

$Mode=30 + \frac{6}{10} \times 10$

$Mode = 30 + 6$

$Mode = 36$