Physics, asked by cutenitin2004, 9 months ago

Plz solve this question. In a simple pendulum experiment a student calculate the value of g is 9.92m/s^2 but standard value of g is 9.80 m/s^2 then % errors in the calculation of the g​ is.

Answers

Answered by ashutoshfeb24
2

Answer:

1.22%

Explanation:

Error = 9.92 - 9.8 = 0.12

True value = 9.8

%error = error/true value × 100

= 0.12/9.8 ×100

= 1.22 %

HOPE IT HELPS PLZ MARK AS BRAINLEIST

Similar questions