Question

Plz solve this question. In a simple pendulum experiment a student calculate the value of g is 9.92m/s^2 but standard value of g is 9.80 m/s^2 then % errors in the calculation of the g​ is.

Answer 1

Answer:

1.22%

Explanation:

Error = 9.92 - 9.8 = 0.12

True value = 9.8

%error = error/true value × 100

= 0.12/9.8 ×100

= 1.22 %

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