Question

plz solve this question it is very important

Answer 1

Step-by-step explanation:

for equal roots

condition is B^2-4ac=0

so,,

4(k+1)^2=4k^2.

k^2+2k+1=k^2

2k=-1

k=-1/2

Answer 2

QUESTION

The value of k for which the equation

x^2 + 2 ( k + 1 ) x + k^2 = 0 has equal roots is.

SOLUTION

For equation has equal roots

D = b^2 - 4ac = 0

2 ( k + 1 ) ^2 - 4(1) (k^2) = 0

4 ( k^2 + 1 + 2k ) - 4k^2 = 0

4k^2 + 4 + 8k - 4k^2 = 0

4 + 8k = 0

k = -1/2

Hence,

option (B) is correct

SOME RELATED FORMULA

• D > 0 Roots are real and unequal
• D = 0 Roots are real and equal
• D < 0 Roots are Imaginary