Plz solve this.... question no. (c)....
Attachments:

Answers
Answered by
0
since focal length is 8 cm then then the radius of curvature is 8 * 2 = 16 .
Since object is even behind the centre of curvature the object needs to be real , inverted and between focal length and 2F .
Therefore
1. Real and inverted
2. Lens formula is 1\v = 1\f + 1\u. ( where v = image distance , u = object distance and f = focal length )
1\v = 1\8 + 1\-24
Therefore v = image distance = (+12) cm
3. magnification = - image distance\ object distance
OR
m = -v\u
= -12\-24
= 1\2
= 0.5
Similar questions