plz solve this question of trigonometry
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3
Answer:
sin 5x +sin 3x/ cos 5x+ cos 3x
2 sin ( 5x+3x/2) cos (5x -3x/2) / 2 cos (5x+3x/2) cos (5x-3x/2)
sin (8x/2) cos (2x/2)/ cos (8x/2)cos (2x/2)
sin 4x/cos 4x
tan x
Answered by
6
sin 5x + sin 3x
=====>
Using sin x + sin y
=
2 sin[(x+y)/2] cos [ (x-y)/2]
Putting x = 5x & y = 3x
2 sin[(5x + 3x)/2] cos[(5x - 3x)/2]
2 sin(8x/2) cos(2x/2)
2 sin 4x cos x (1)
cos 5x + cos 3x
======>
Using cos x +cos y
=
2cos [( x+y)/2] cos[(x-y)/2]
Putting x = 5x & y = 3x
2 cos[(5x +3x)/2] cos[( 5x -3 x)/2]
2 cos(8x/2) cos(2x/2)
2 cos 4x cos x. (2)
Dividing 1 and 2
2 sin 4x cos x/ 2 cos 4x cos x
sin 4x/ cos 4x
=======>
tan 4x. ( sin/cos = tan)
Hence proved
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