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one of the can holds 2 1/6 L of juice
amt of juice in the other can is x
total amt of juice = 4 3/4
so,
2 1/6 +x = 4 3/4
x = 4 3/4 - 2 1/6
x = 19/4 - 13/6
x = 57-26/12 (12 is the denominator ;due to LCM)
x = 31/12
x = 2 7/12
therefore the other can holds 2 7/12L of juice.
amt of juice in the other can is x
total amt of juice = 4 3/4
so,
2 1/6 +x = 4 3/4
x = 4 3/4 - 2 1/6
x = 19/4 - 13/6
x = 57-26/12 (12 is the denominator ;due to LCM)
x = 31/12
x = 2 7/12
therefore the other can holds 2 7/12L of juice.
abcd195:
how 21/6
Answered by
0
One of the can holds 2 1/6 L of juice
amt of juice in the other can is x
total amt of juice = 4 3/4
so,
2 1/6 +x = 4 3/4
x = 4 3/4 - 2 1/6
x = 19/4 - 13/6
x = 57-26/12 (12 is the denominator ;due to LCM)
x = 31/12
x = 2 7/12
therefore the other can holds 2 7/12L of juice
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