Plz, solve this question Q.no. Any one of Q. 6th
Attachments:

Answers
Answered by
0
i think its right but not sure
Attachments:

GelageetKumar:
Wrong answer
Answered by
0
x^2(x+2y)(x-3y)
=x^2(x^2-3xy+2xy-6y^2)
=x^4-x^3y-6x^2y^2
then subtitue values
=(-1)^4-(-1)^3(-2)-6(-1)^2(-2)^2
=1-1(-2)-6(1)(4)
=1+2-24
=-21
=x^2(x^2-3xy+2xy-6y^2)
=x^4-x^3y-6x^2y^2
then subtitue values
=(-1)^4-(-1)^3(-2)-6(-1)^2(-2)^2
=1-1(-2)-6(1)(4)
=1+2-24
=-21
Similar questions