plz solve this question ques 47
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the two zeros are -1 and -1
x^2+2x+1
x^2+x+x+1
x[x+1] 1[x+1]
[x+1], [x+1]
Put both equal to zero
L.H.S
x+1=0
x=-1
R.H.S
x+1=0
x=-1
x^2+2x+1
x^2+x+x+1
x[x+1] 1[x+1]
[x+1], [x+1]
Put both equal to zero
L.H.S
x+1=0
x=-1
R.H.S
x+1=0
x=-1
Answered by
0
Hey friend ...!! here's your answer
__________________________
x^2 + 2x +1
x^2 + x + x + 1
x(x+1) +1 (x+1)
(x + 1) (x + 1)
x = -1 and x= -1
_________________________
#Hope its help you dear#
☺
__________________________
x^2 + 2x +1
x^2 + x + x + 1
x(x+1) +1 (x+1)
(x + 1) (x + 1)
x = -1 and x= -1
_________________________
#Hope its help you dear#
☺
Anonymous:
if its help u..then....plss mark as brainlist...
thbk you so much.
thnk**
i marked u as brainlist because u have sloved it step by step na
hm...
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