Math, asked by kk6510741, 8 months ago

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Answered by ritubhatt081984
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Answer:

  1. Let the sides of a given triangle be a = 25x, b = 17x, c = 12x respectively, Given, Perimeter of triangle = 540 cm 2s = a + b + c a + b + c = 540 cm 25x + 17x + 12x = 540 cm 54x = 540 cm x = 10 cm So, the sides of a triangle are a = 250 cm b = 170 cm c = 120 cm Semi perimeter, s=(a+b+c)2s=(a+b+c)2 = 54025402 = 270 s = 270 cm Hence, the area of the triangle is 9000 cm2

2. Side of square will be equal to the diameter of circle. So the radius of circle is half of 14 i.e. 7cm. Area of enclosed part is area of square minus area of circle. =42cm^2.

3. answer 3 is attached in the above pic

so the perimeter = 50cm

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