Question

plz solve this question step by step

Answer 1

$Given : 5^{n + 2} = 625$

$= \ \textgreater \ 5^{n + 2} = 5^4$

$= \ \textgreater \ n + 2 = 4$

$= \ \textgreater \ n = 4 - 2$

$= \ \textgreater \ n = 2.$


Now,

$Given : \sqrt[3]{n + 727}$

= > $\sqrt[3]{2 + 727}$

$= \ \textgreater \ \sqrt[3]{729}$

$= \ \textgreater \ \sqrt[3]{9^3}$

$= \ \textgreater \ 9$


Hope this helps!

Answer 2

$given \: \ \ {5}^{n + 2} = 625 \\ {5}^{n + 2} = {5}^{4} \\ n + 2 = 4 \\ n = 4 - 2 = 2 \\ n = 2 \\ consider \: \sqrt[3]{n + 727} \\ = \sqrt[3]{2 + 727} \\ = \sqrt[3]{729} \\ = \sqrt[3]{ {9}^{3} } \\ = {( {9}^{3}) }^{ \frac{1}{3} } \\ = {9}^{3 \times \frac{1}{3} } \\ = {9}^{1} \\ = 9$