Question

Plz solve this question then i will mark your answer as brainliest

Answer 1

proof- In ΔPQR, QR is produced to S

          so,∠PRS = ∠QPR  + ∠PQR (EXTERIOR ANGLE PROPERTY)
                 1/2 ∠PRS = 1/2∠QPR  + 1/2∠PQR
                
                  ∠TRS =  1/2 ∠QPR + ∠TQR - (1) <QT and RT are the angle                                                            bisector of∠PQR and ∠PRS  respectively >

In ΔTQR, QR is produced to S

∠TRS = ∠QTR + ∠TQR -(2)

From equation (1) & (2)
            
1/2 ∠QPR + ∠TQR = ∠QTR + ∠TQR

Hence, ∠QTR = 1/2 ∠QPR  (PROVED)