plz solve this question with explanation....
Answers
Answer
In fig 1 exterior angle = 120° and in fig 2 exterior angle = 135 °
I am solve this by a property known as exterior angle property of triangle.
Answer:
1) 120°
2) 135°
Step-by-step explanation:
Fig 1 is an equilateral triangle,
So, all angles are 60°
∠ACB and ∠ACD form a linear pair.
⇒ ∠ACB + ∠ACD = 180°
⇒ 60° + ∠ACD = 180°
⇒ ∠ACD = 180° - 60°
⇒ ∠ACD = 120°
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Fig 2 is a right Δ,
∠ABC + ∠BAC + ∠BCA = 180°................(1)
Given, BA = BC
⇒ ∠BAC = ∠BCA
in (1)
90° + ∠BCA + ∠BCA = 180°
2∠BCA = 90°
∠BCA = 45°
∠BCA and ∠ACD form a linear pair.
⇒ ∠BCA + ∠ACD = 180°
⇒ 45° + ∠ACD = 180°
⇒ ∠ACD = 180° - 45°
⇒ ∠ACD = 135°
If this helps please mark it as best ; )