Math, asked by aroraekta409, 11 months ago

plz solve this question with explanation....​

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Answered by bhagatsumit674
0

Answer

In fig 1 exterior angle = 120° and in fig 2 exterior angle = 135 °

I am solve this by a property known as exterior angle property of triangle.

Answered by sammaria
1

Answer:

1) 120°

2) 135°

Step-by-step explanation:

Fig 1 is an equilateral triangle,

So, all angles are 60°

∠ACB and ∠ACD form a linear pair.

⇒ ∠ACB + ∠ACD = 180°

⇒ 60° + ∠ACD = 180°

⇒           ∠ACD = 180° - 60°

⇒            ∠ACD = 120°

=================================================================

Fig 2 is a right Δ,

∠ABC + ∠BAC + ∠BCA = 180°................(1)

Given, BA = BC

⇒ ∠BAC = ∠BCA

in (1)

90° + ∠BCA + ∠BCA = 180°

           2∠BCA = 90°

            ∠BCA = 45°

∠BCA and ∠ACD form a linear pair.

⇒ ∠BCA + ∠ACD = 180°

⇒ 45° + ∠ACD = 180°

⇒           ∠ACD = 180° - 45°

⇒            ∠ACD = 135°

If this helps please mark it as best ; )

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