Question

A tank fills completely in 2 hrs if both the taps are open. If only one of the
taps is open at the given time, the smaller tap takes 3 hrs more than the
larger one to fill the tank. How much time does each tap take to fill the tank
completely​

Answer 1

Answer:

Hey!!

Let the time taken by one pipe be 'x'hrs.

then; other pipe takes '3+x'hrs....(small)

ATQ:

1/x+1/(3+x)=1/2

=>(3+x+x)/x²+3x=1/2

=>(3+2x)2=(x²+3x)

=>6+4x=x²+3x

=>x²–x–6=0

=>x²–3x+2x–6=0

=>x(x–3)+2(x–3)=0

=>(x+2)(x–3)=0

Thus, either, (x+2)=0 OR (x–3)=0

=>x=–2 OR=>(x=3)

(discarded)

Therefore, the time taken by the bigger pipe is "3hrs"

and, time taken by pipe is "6hrs"

I hope it helps you ^_^

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Answer 2

Answer:

Thats the answer you want... But be careful when you convert them to individual times.......