Question

plz solve this questions

Answer 1

Angle A = 40°
CE II BA
BD is transversal

Angle ECD = Angle ABC = 55° ( corresponding angles)

Angle sum property
Angle BAC + Angle ABC + Angle ACB = 180
40° + 55° + Angle ACB = 180°
95 + Angle ACB = 180
Angle ACB = 180 - 95
Angle ACB = 85°

Angle ACB = 85°
Angle ABC = 55°

Answer 2

Answer:

Step-by-step explanation:

as ∠ECD and∠ABC lie on EC and AB respectively and BD is a transversal.

∠ECD = ∠ABC = 55°

In ΔABC,

∠A +∠B +∠C =180°           (angle sum property )

40°+55°+∠ACB = 180°

95° +∠ACB = 180°

∠ACB =180° -95°

∠ACB = 85°