plz solve this quickly
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Area of square courtyard = 59
side of square courtyard = √59 = 7.67
Area of square + path = 59 +120= 179
side of square + path = √179 = 13.4
7.67 + 2x = 13.4
2x = 5.73
x = 2.865
so width = 2.865
side of square courtyard = √59 = 7.67
Area of square + path = 59 +120= 179
side of square + path = √179 = 13.4
7.67 + 2x = 13.4
2x = 5.73
x = 2.865
so width = 2.865
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Hello Mate!
Since we know that,
Area of outer Park - area of inner park = area of path.
Area of inner park = 59 m²
Area of outer park - 59 = 120 m²
Area of outer park = 120 + 59
Area of outer Park = 179 m² _(i)
In Inner Park,
Length = breadth .
Side² = 179 m²
Side = 13.4 m
In outer Park,
Length = breadth
Side² = 59 m²
Side = 7.7 m
Since we know that,
Outer length = inner length + 2( width )
Let the width be x,
13.4 m = 7.7 m + 2x
5.7 m = 2x
2.85 m = width.
"Have great future ahead!"
Since we know that,
Area of outer Park - area of inner park = area of path.
Area of inner park = 59 m²
Area of outer park - 59 = 120 m²
Area of outer park = 120 + 59
Area of outer Park = 179 m² _(i)
In Inner Park,
Length = breadth .
Side² = 179 m²
Side = 13.4 m
In outer Park,
Length = breadth
Side² = 59 m²
Side = 7.7 m
Since we know that,
Outer length = inner length + 2( width )
Let the width be x,
13.4 m = 7.7 m + 2x
5.7 m = 2x
2.85 m = width.
"Have great future ahead!"
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