Question

plz solve this sum tomorrow is my test and with solution ​

Answer 1

let Devesi have x , y and z note of 50 , 20 and 10 respectively.
Given :
x:y = 3:5
or, x/y = 3/5
or, x = 3y/5
Again ,
x +y + z = 25
3y/5 + y + z = 25
8y/ 5 + z = 25
z = 25 - 8y/5

According to question

$50x + 20y + 10z = 590 \\ 50 \times \frac{3y}{5} + 20y + 10(25 - \frac{8y}{5} ) = 590 \\ 30y + 20y + 250 - 16y = 590 \\ 50y - 16y = 590 - 250 \\ 34y = 340 \\ y = 10 \: \: \: \: \: x = \frac{3y}{5} = \frac{30}{5} = 6$
$z =25 - \frac{8y}{5} \\ 25 - \frac{80}{5} \\ 25 - 16 \\ 9$

Answer 2

Answer:

Follow the attachment...