Question

Plz solve this with an appropriate figure

Answer 1

ok let's see

figure is in the attachment

SOLVING ACCORDING TO THE FIGURE

GIVEN:

AB=PQ(HYPOTENUSE)

AC=PR(ONE SIDE)

TO PROVE:

∆ABC is congurent to ∆PQR

PROOF:

AS AB=PQ

AB^2=PQ^2

ACCORDING TO

PYTHAGORAS BABA (JAI HO)

AB^2=AC^2+BC^2

PQ^2=PR^2+QR^2

SO AS

AB^2=PQ^2

AC^2+BC^2=PR^2+QR^2

AND AS WE KNOW IT IS GIVEN AC=PR

THEN AC^2=PR^2

SO

AC^2-PR^2+BC^2=QR^2

BC^2=QR^2

BC=QR

SO IN ∆ABC AND ∆PQR

ALL THE THREE SIDES ARE EQUAL AB=PQ;BC=QR;AC=PR

THEREFORE

∆ABC is congurent to ∆PQR

BY S.S.S(SIDE SIDE SIDE)

CRITERIA. HENCE PROVED.#

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