Math, asked by Anonymous, 1 year ago

plz solve thisssssss.......................

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Answered by siddhartharao77
1
Formula is root(x2-x1)^2 +(y2-y1)^2+(z2-z1)^2

= (x-3)^2 + (y-4)^2 +(z-5)^2 + (x+1)^2 + (y-3)^2  + (z+7)^2 = 2k^2

= 2x^2 + 2y^2 +2z^2 -4x - 14y + 4z = 2k^2 - 109

= 2x^2 + 2y^2 +2z^2 -4x - 14y + 4z - 2k^2 + 109 = 0.
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