plz.. solve with steps
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c2 = h2+(a-x)2
b2=h2+x2
on adding ,we have 2h2+x2+(a-x)2=a2. 1
also a=4h and cos B =b/a=x/b
so x=b2/a
on solving 1 ,we have h2+x2-4hx=0
substituting above gives b4+a4/16-a2.b2=a. 2
as cis B =b/a
on solving equn 2 we have
cos2B = 0.933or 0.067
cos B =0.966or0.259
B= 15 or 75degree
as B is acute angle ,B is 15 degrees
b2=h2+x2
on adding ,we have 2h2+x2+(a-x)2=a2. 1
also a=4h and cos B =b/a=x/b
so x=b2/a
on solving 1 ,we have h2+x2-4hx=0
substituting above gives b4+a4/16-a2.b2=a. 2
as cis B =b/a
on solving equn 2 we have
cos2B = 0.933or 0.067
cos B =0.966or0.259
B= 15 or 75degree
as B is acute angle ,B is 15 degrees
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can you explain how c2 came
root over k place m 2 dalte h
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