Plz solve with the process
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√0.18,
√(18/100),
√(3×3×2)/√(10×10),
3√2/10,
3×1.41/10,
4.23/10,
0.42
√(18/100),
√(3×3×2)/√(10×10),
3√2/10,
3×1.41/10,
4.23/10,
0.42
princesssarkar:
no answer is 0.402
Answered by
1
Hi there here's the answer:
√0.18=√(18/100)= √(18)/√(100)
we have 10²= 100
=> √100= 10
=> √0.18 = √(18)/10
Now find square root of 18
18 is a non perfect square
Estimating square roots for non perfect square 'x':
• Consider the no. in b/w 2 perfect squares
16<18<25
4²<18<5²
•°• 4<√18<5
√18 lies in b/w 4 & 5
• Find whether the no. is nearer to lower perfect square or higher perfect square
18-16= 2
25-18= 7
(Note value whichever is lower, say d)
d= 2
•°• 18 is nearer to lower perfect square 16(i.e., 4²)
•°• √18= 4+ ……
( Here note this value, say a)
a= 4
• Now find No. of No.s b/w the 2 perfect squares
=> There are (2×a) Non perfect squares b/w a² and (a+1)²
•°• No. of no.s b/w 4² and 5² = 2×4=8
(Note this Value, say n)
√x= a + (d/n)
•°• √18= 4 + (2/8)
=> √18= 4 + (1/4)
1/4= 0.25
√18= 4.25
•°• √0.18= √18/10= 4.25/10= 0.425.
;)
hope it helps
comment if you need to clear anything
√0.18=√(18/100)= √(18)/√(100)
we have 10²= 100
=> √100= 10
=> √0.18 = √(18)/10
Now find square root of 18
18 is a non perfect square
Estimating square roots for non perfect square 'x':
• Consider the no. in b/w 2 perfect squares
16<18<25
4²<18<5²
•°• 4<√18<5
√18 lies in b/w 4 & 5
• Find whether the no. is nearer to lower perfect square or higher perfect square
18-16= 2
25-18= 7
(Note value whichever is lower, say d)
d= 2
•°• 18 is nearer to lower perfect square 16(i.e., 4²)
•°• √18= 4+ ……
( Here note this value, say a)
a= 4
• Now find No. of No.s b/w the 2 perfect squares
=> There are (2×a) Non perfect squares b/w a² and (a+1)²
•°• No. of no.s b/w 4² and 5² = 2×4=8
(Note this Value, say n)
√x= a + (d/n)
•°• √18= 4 + (2/8)
=> √18= 4 + (1/4)
1/4= 0.25
√18= 4.25
•°• √0.18= √18/10= 4.25/10= 0.425.
;)
hope it helps
comment if you need to clear anything
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