Question

Plz Someone Help Me Answer This Question With Solution
And Take pie=3.14

Answer 1

Answer:

As

In triangle height is 9in

base is 12in

It have 2 right angle triangle with base 6in

Area of triangle = 2 ( area of right angle triangle)

= 2 (1/2 × B ×H )

= 2 ( 1/2 × 6× 9)

= 2 ( 27)

= 54 in^2

Now the area of semi circle with radius 6 in

= 1/2 pie r^2

= 1/2 × 3.14 × 6 × 6

= 3.14 × 3 × 6

= 56.52 in^2

Area of the shape = Area of triangle + Area of semi circle

= 54in^2 + 56.52in^2

= 110.52 in^2

Answer 2

$\huge\bold \color{brown}{\boxed{☆Answer ☆}}$

Given:-

In triangle

Height = 9inch

Base = 12 inch

In semicircle

Diameter= 12 inch

Radius = 6 inch

Area of triangle =

$\color{brown}{ \boxed{\frac{1}{2} \times base \times hight}}$

$= > \frac{1}{2} \times 9 \times 12$

$= > 1 \times 9 \times 6$

$= > 54 \: \: inch$

Area of triangle is 54 inch.

Area of semicircle

$\color{brown}{ = > \boxed{ \frac{\pi {r}^{2} }{2} }}$

$= > \frac{3.14 \times {(6)}^{2} }{2}$

$= > \frac{3.14 \times 36}{2}$

$= > 3.14 \times 18$

$= > 56.52$

Therefore area of semicircle is 56.52 inches .

Area of whole figue

$\boxed{ = > Area \: \: of \: \: semicircle + Area \: \: of \: \: traingle}$

=> 54 + 56.52

=> 110.52

Area of whole figure is 110.52 inches.

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I hope it will help you.......