Question

plz sove 18 i am unable to solve plz help

Answer 1

the answer is (b) , y = 3x.

Answer 2

Distance traveled in first 10 seconds
[tex]x = ut_{1} + \frac{1}{2}at_{1} ^{2} \\ x=0(10)+ \frac{1}{2}a(10 ^{2}) \\ x= 50 a [/tex]

Distance traveled in next 10 seconds
$y= (ut_{2} + \frac{1}{2}at_{2} ^{2})-(ut_{1} + \frac{1}{2}at_{1} ^{2}) \\ y= (u(20) + \frac{1}{2}a20 ^{2})-(u(10) + \frac{1}{2}a(10 ^{2}) \\ y= 200a - 50 a \\ y=150 a$

Comparing both results
[tex]a= \frac{x}{50} \\ a= \frac{y}{150} \\ \frac{x}{50}= \frac{y}{150} \\ y= 3x [/tex]