plz tell and it's answer is coming 2 or 4
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25^(x-1) = 5^(2x-2)
5^(2x-2) = 5^(2x-1) - 100
100 = 5 ^(2x-1) - 5^(2x-2)
100 = 5^(2x-1) - [5^(2x-1)/5)]
Let 5^(2x-1) = a
100 = a - a/5
4a/5 = 100
a = 125 = 5³
So, 5^(2x-1) = 5³
Since bases are equal, exponents must be equal
So, 2x - 1 = 3
2x = 4
x = 2
5^(2x-2) = 5^(2x-1) - 100
100 = 5 ^(2x-1) - 5^(2x-2)
100 = 5^(2x-1) - [5^(2x-1)/5)]
Let 5^(2x-1) = a
100 = a - a/5
4a/5 = 100
a = 125 = 5³
So, 5^(2x-1) = 5³
Since bases are equal, exponents must be equal
So, 2x - 1 = 3
2x = 4
x = 2
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