Question

plz tell fast I have an exam​

Answer 1

Answer:

IN  ΔABC, AB=AC (GIVEN)

⇒∠A=∠C  (ANGLES OPP TO EQUAL SIDES ARE EQUAL)

IN ΔABD AND ΔCBE

AB=AC  (GIVEN)

AD=CE   (GIVEN)

∠A=∠C   (PROVED ABOVE)

ΔABD≅ΔCBE    (BY SAS CONGRUENCY)

BD=BE (CPCT)

Step-by-step explanation:

Answer 2

Answer:

Give that

AB = AC

AD = AC

In ∆ABD

AB = AC [ Given ]

Angle A = Angle C

From ∆ABD and ∆CBE

AB = AC [ Adjacent side ]

angle A = angle C [ Angles ]

AD = CE [ Adjacent side ]

By SAS congruency rule

∆ABD similar to ∆CBE

By CPCT

BD = BE