plz tell fast I have an exam
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Answer:
IN ΔABC, AB=AC (GIVEN)
⇒∠A=∠C (ANGLES OPP TO EQUAL SIDES ARE EQUAL)
IN ΔABD AND ΔCBE
AB=AC (GIVEN)
AD=CE (GIVEN)
∠A=∠C (PROVED ABOVE)
ΔABD≅ΔCBE (BY SAS CONGRUENCY)
BD=BE (CPCT)
Step-by-step explanation:
Answered by
1
Answer:
Give that
AB = AC
AD = AC
In ∆ABD
AB = AC [ Given ]
Angle A = Angle C
From ∆ABD and ∆CBE
AB = AC [ Adjacent side ]
angle A = angle C [ Angles ]
AD = CE [ Adjacent side ]
By SAS congruency rule
∆ABD similar to ∆CBE
By CPCT
BD = BE
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