Question

plz tell me.....how can it solve ? ​

Answer 1

Answer:

photo is not clear tan : 00 cos sytecretic s

Answer 2

Answer:

$\frac{sin \: θ - 2 {sin}^{3}θ }{2 {cos}^{3}θ - cos θ} = tanθ$

$\frac{sinθ(1 - 2 {sin}^{2}θ) }{cosθ(2 {cos}^{2} θ - 1)} = tanθ$

$\frac{sinθ(1 - {sin}^{2}θ + {sin}^{2} θ) }{cosθ( {cos}^{2}θ + {cos}^{2}θ - 1) } = tanθ$

$\frac{sinθ( {cos}^{2}θ + {sin}^{2}θ)}{cosθ( {sin}^{2} θ + {cos}^{2}θ) } = tanθ$

$\frac{ sinθ(1)}{cosθ(1)} = tanθ$

$\frac{sinθ}{cosθ} = tanθ$

$tanθ = tanθ$

L.H.S.=R.H.S.

Hence proved