Question

Plz tell me the 5th Question

Answer 1

$\frac{ \sqrt{162} + \sqrt{108} }{ \sqrt{72} + \sqrt{48} } = \frac{9 \sqrt{2} + 6 \sqrt{3} }{6 \sqrt{2} + 4 \sqrt{3} } \\ = \frac{(9 \sqrt{2} + 6 \sqrt{3} )( 6 \sqrt{2} - 4 \sqrt{3} )}{(6 \sqrt{2} + 4 \sqrt{3} )(6 \sqrt{2} - 4 \sqrt{3} ) } \\ \frac{108 - 36 \sqrt{6} + 36 \sqrt{6} - 72}{72 - 48} \\ = \frac{36}{24} = \frac{3}{2}$