plz tell the ans. .......
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Hey there!!
Let, y = sin³x
Then using chain rule,
=>dy/dx = d(sin³x) /d(sinx) × d(sinx) /dx = 3sin²x cosx
Hope it will help u...
#abhimanyu
Let, y = sin³x
Then using chain rule,
=>dy/dx = d(sin³x) /d(sinx) × d(sinx) /dx = 3sin²x cosx
Hope it will help u...
#abhimanyu
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