Question

plz tell the answer if you will tell me correct answer i will mark you brainlist​ ​

Answer 1

Answer:

Simply to prove that if a + b + c = 0, then a^3 + b^3 + c^3 - 3abc = 0. Indeed, we have:

(a + b + c)^3

= a^3 + b^3 + c^3 + 3a^2.b + 3a.b^2 + 3b^2c + 3b.c^2 + 3^2.a + 3c.a^2 + abc

= a^3 + b^3 + c^3 + 3(ab + bc + ac)(a + b + c) - 3abc

Since a + b + c = 0, so a^3 +b^3 +c^3 - 3abc = 0 (Q.E.D)

Return to the problem, we have:

a + b+c = 27 => (a - 7) + (1 - 9) +(c - 11) = 0.

So, (a - 7)^3 + (b-9)^3 + (C-11)^3 - 3(a - 7)(b - 9)(c - 11) =0