Plz tell the answer of 29th question both parts
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cos =root 4-a2/2
sec =2/root 4-a2
sin=a2 +2root4a /2
coses= 2/a2+2root4a
tan=root 4-a2/ a2 +2root 4a
now by multiplying we can get the answer
sec =2/root 4-a2
sin=a2 +2root4a /2
coses= 2/a2+2root4a
tan=root 4-a2/ a2 +2root 4a
now by multiplying we can get the answer
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