plz tell the solution plz
Attachments:
Answers
Answered by
0
Here is your answer
Attachments:
jyothibanavathpa9g2y:
thank you broo
Answered by
0
For all values of the angle A we know that, (sin A2A2 + cos A2A2)22 = sin22 A2A2 + cos22 A2A2 + 2 sin A2A2 cos A2A2 = 1 + sin A
Therefore, sin A2A2 + cos A2A2 = ± √(1 + sin A), [taking square root on both the sides]
Now, let A = 30° then, A2A2 = 30°230°2 = 15° and from the above equation we get,
sin 15° + cos 15° = ± √(1 + sin 30°) ….. (i)
Similarly, for all values of the angle A we know that, (sin A2A2 - cos A2A2)22 = sin22 A2A2 + cos22 A2A2 - 2 sin A2A2 cos A2A2 = 1 - sin A
Therefore, sin A2A2 - cos A2A2 = ± √(1 - sin A), [taking square root on both the sides]
Therefore, sin A2A2 + cos A2A2 = ± √(1 + sin A), [taking square root on both the sides]
Now, let A = 30° then, A2A2 = 30°230°2 = 15° and from the above equation we get,
sin 15° + cos 15° = ± √(1 + sin 30°) ….. (i)
Similarly, for all values of the angle A we know that, (sin A2A2 - cos A2A2)22 = sin22 A2A2 + cos22 A2A2 - 2 sin A2A2 cos A2A2 = 1 - sin A
Therefore, sin A2A2 - cos A2A2 = ± √(1 - sin A), [taking square root on both the sides]
Similar questions
English,
8 months ago
Physics,
8 months ago
Hindi,
1 year ago
Business Studies,
1 year ago
Math,
1 year ago