plz tell this answer
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Start with the formulas for volume and slant area in terms of h and r:
V = (π/3) r² h ... volume of a cone
C = π r √(h² + r²) ... lateral area of a cone
Looking again, that "22/7" in your first term looks suspiciously like an approximation to π. If it is, the statement is false. It is at best an "approximately equal" statement. Test:
3π V h^3 =
C² h² = π² r² (h² + r²) h²
9V² = π² r^4 h²
So, combine those:
3πVh^3 - C²h² + 9V² = (π² r² h^4) - [π² r² (h² + r²) h²] + (π² r^4 h²)
= π² r² h² [ h² - (h² + r²) + r²] ... factoring out π², r² and h² from each term
But the [] bracketed sum is h² - h² - r² + r² = 0, for any values of h and r, so the product is also zero, and that' proves that:
3πVh^3 - C²h² + 9V² = π² r² h² (0) = 0
V = (π/3) r² h ... volume of a cone
C = π r √(h² + r²) ... lateral area of a cone
Looking again, that "22/7" in your first term looks suspiciously like an approximation to π. If it is, the statement is false. It is at best an "approximately equal" statement. Test:
3π V h^3 =
C² h² = π² r² (h² + r²) h²
9V² = π² r^4 h²
So, combine those:
3πVh^3 - C²h² + 9V² = (π² r² h^4) - [π² r² (h² + r²) h²] + (π² r^4 h²)
= π² r² h² [ h² - (h² + r²) + r²] ... factoring out π², r² and h² from each term
But the [] bracketed sum is h² - h² - r² + r² = 0, for any values of h and r, so the product is also zero, and that' proves that:
3πVh^3 - C²h² + 9V² = π² r² h² (0) = 0
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