Question

plz try this sum... its of class 10th from the chapter trigonometry..

Answer 1

s this question is tough
the ans is
2(sin^6 theta + cos^6 theta) = 3(sin4 theta +cos 4 theta) + sin2 theta + cos2 theta

Answer 2

2(sin⁶θ+cos⁶θ)-3(sin⁴θ+cos⁴θ)+1
= 2{(sin²θ)³+(cos²θ)³}-3{(sin²θ)²+(cos²θ)²}+1
= 2{(sin²θ+cos²θ)³-3sin²θcos²θ(sin²θ+cos²θ)}-3{(sin²θ+cos²θ)²-2sin²θcos²θ}+1
=2(1-3sin²θcos²θ)-3(1-2sin²θcos²θ)+1
=2-6sin²θcos²θ-3+6sin²θcos²θ+1
=-1+1
=0 (Proved)

mark it as brainliest!! plzz frnd!!