Question

plz with solution
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Answer 1

Given :

• Force acting on the object is 25 N at angle 30° to the direction of displacement

• Displacement due to the act of force = 4 m

To find :

• The work done

Solution :

The work done on a body when a force 'F' N acts at angle 'θ' causing a displacement of 'S' m is given by ,

$\star \: \large{ \boxed{ \purple{ \sf{W = F.S \cos(\theta)}}}}$

We have ,

• F = 25 N
• θ = 30°
• S = 4 m

$\bigstar \underline{ \sf{By \: substituting \: the \: values ,\: }}$

$\\ : \implies \sf \: W = (25 \: N)(4 \: m)( \cos30 {}^{ \circ} ) \\ \\ \\ : \implies \sf \: W = 100Nm( \cos{30}^{ \circ} ) \\ \\ \\ : \implies \sf \: W = 100 \: Nm \bigg( \frac{ \sqrt{3} }{2} \bigg) \\ \\ \\ : \implies \sf \: W = 100 \: J \bigg( \frac{ \sqrt{3} }{2} \bigg) \\ \\ \\ : \implies \sf \: W = 50 \: J( \sqrt{3} ) \\ \\ \\ : \implies {\boxed {\underline{\sf{W = 50 \sqrt{3} \: J }}}}$

Hence , The work done is $\sf{50\sqrt{3}}$ J

Note :

$\longmapsto \sf \: \cos{30}^{ \circ} = \dfrac{ \sqrt{3} }{2} \\ \\ \\ \longmapsto \sf \: 1J= 1Nm$

Answer 2

$\huge{\underline{\underline{\boxed{\sf{\purple{Answer ࿐}}}}}}$

The work done on a body when a force 'F' N acts at angle 'θ' causing a displacement of 'S' m is given by ,

❝$\small{\underline{\underline{\boxed{\sf{\green{W = F.Scos(θ) }}}}}}$❞

We have ,

F = 25 N

θ = 30°

S = 4 m

★ By substituting the values,

• ⟹ W = (25N) (4m) (cos30∘)

• ⟹ W = 100Nm (cos30∘)

• ⟹ W = 100Nm (√3/2)

• ⟹ W=100J (√3/2)

• ⟹ W = 50J (√3)

• ⟹ W = 50√3J

$\small \underline {\sf{ Hence \ , \ The \ work \ done \ is  \ 50√3 \ J}}$