Question

Plzz ans....EMPIRICAL AND MOLECULAR FOEMULA.....Question is in ATTACHMENT

Answer 1

HELLO DEAR,

GIVEN that: Molecular mass of the compound = 122 g
0.26g of Al is present in 1.3g sample of the compound.

mass of Al pressent in 122 g of the same compound = (0.26/1.3) × 122
                                                                                  = 24.4 ≈ 27
Similarly mass of P present in 122 g of the same compound =( 0.35/1.3) × 122
                                                                                       = 32.84 ≈ 31
And mass of O in it = (  0.682 / 1.3 ) × 122 = 64.0030 ≈ 64

Comparing these values with the molecular masses of the respective compounds , we find that a molecule of the given compound contains 1 Al atom , 1 P atom and 4 O atoms...

Hence the molecular formula of the compound is AlPO₄ .

$PE ITS HELP YOU DEAR, \\ THANKS$