Question

plzz ans guys.....


Find the point on y axis which is equidistant from(6,5),(-4,3)​

Answer 1

gud mrng......bhai......

.

.

.

.

.

Let P is equidistance point P(x,y)

x = -4+6/2=2/2=1

y=3+5/2 =8/2 =4

so P(1,4)

.

.

.

.

.

hope it helps uh..✔️

Answer 2

we can use distance formula=√(a2-a1)2+(b2-b1)2
(X,0)
and Equate both side...by using
a(6,5),b(X,0)= b(X,0),c(-4,3)
ab=BC
you can find answer
very easily...
please try to do