plzz ans it step by step
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Step-by-step explanation:
5.(i)(a^2-b^2)(ab)=a^3-b^3
(ii)(2p^2q^2-3pq^3+4q^4)(-2pqr)
= -4p^3q^3r+6p^2q^4r-8pq^5r
(iii)(bc+ca-ab)(-2abc)
= -2ab^2c^2-2a^2bc^2+2a^2b^2c
(iv)(-3/8x^5y^3z)(16xyz)
= -6x^6y^4z^2
6.(i)ab(3a-5b)
=3a^2b-5ab^2
(ii)6mn(2m-3n)
=12m^2n-18mn^2
(iii)(x^2-5x-6)(x-4)
=x(x^2-5x-6)-4(x^2-5x-6)
=x^3-5x^2-6x-4x^2+20x+24
=x^3-9x^2+14x+24
(iv)(a^2-ab+b^2)(a+b)
=a(a^2-ab+b^2)+b(a^2-ab+b^2)
=a^3-a^2b+ab^2+a^2b-ab^2+b^3
=a^3+b^3
(v)(3a+2b)(5a-7b)
=3a(5a-7b)+2b(5a-7b)
=15a^2-21ab+10ab-14b^2
=15a^2-11ab-14b^2
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