Math, asked by jbfan67, 7 months ago

plzz ans it step by step​

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Answered by Thenavi
0

Step-by-step explanation:

5.(i)(a^2-b^2)(ab)=a^3-b^3

(ii)(2p^2q^2-3pq^3+4q^4)(-2pqr)

= -4p^3q^3r+6p^2q^4r-8pq^5r

(iii)(bc+ca-ab)(-2abc)

= -2ab^2c^2-2a^2bc^2+2a^2b^2c

(iv)(-3/8x^5y^3z)(16xyz)

= -6x^6y^4z^2

6.(i)ab(3a-5b)

=3a^2b-5ab^2

(ii)6mn(2m-3n)

=12m^2n-18mn^2

(iii)(x^2-5x-6)(x-4)

=x(x^2-5x-6)-4(x^2-5x-6)

=x^3-5x^2-6x-4x^2+20x+24

=x^3-9x^2+14x+24

(iv)(a^2-ab+b^2)(a+b)

=a(a^2-ab+b^2)+b(a^2-ab+b^2)

=a^3-a^2b+ab^2+a^2b-ab^2+b^3

=a^3+b^3

(v)(3a+2b)(5a-7b)

=3a(5a-7b)+2b(5a-7b)

=15a^2-21ab+10ab-14b^2

=15a^2-11ab-14b^2

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