Question

plzz ans....Mensuration.....Thnk you

Answer 1

q2)- BD²=AD²+AB²
BD²=8²+6²
BD²=64+36
BD²=100
BD=√100=10
BC²=BD²+DC²
26²=10²+DC²
676-100=DC²
576=DC²
24=DC
area of ∆ABD=1/2*8*6
area of ∆ABD=24cm²
area of ∆BDC=1/2*24*10
area of ∆BDC=120cm²
IN this question,
area of quadrilateral=area of ∆ABD+area of ∆BDC
area of quadrilateral=24+120
area of quadrilateral=144cm²