plzz ans. this yaaar
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S10 = 10/2 {2a + (10-1) d}
235 = 5 { 2a + 9d}
235 = 10a + 45d
47 = 2a + 9d...... (1)
S5 + S7 = 167
5/2 {2a + (5-1) d} + 7/2 {2a + (7-1) d} = 167
5/2 {2a + 4d} + 7/2 {2a + 6d} = 167
5a + 10d + 7a + 21d = 167
12a + 31d = 167 .....(2)
now solve (1) and (2) and then you will find a and d ...
and then you will find A.P.
235 = 5 { 2a + 9d}
235 = 10a + 45d
47 = 2a + 9d...... (1)
S5 + S7 = 167
5/2 {2a + (5-1) d} + 7/2 {2a + (7-1) d} = 167
5/2 {2a + 4d} + 7/2 {2a + 6d} = 167
5a + 10d + 7a + 21d = 167
12a + 31d = 167 .....(2)
now solve (1) and (2) and then you will find a and d ...
and then you will find A.P.
thanx
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please refer to the attachment
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