plzz ans....Thnk u.....PROVE THE FOLLOWING-:
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Hold on I'm sorry it on my book.....
I hope it helps
I hope it helps
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dishantsinghom:
thanks
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hey !!
Given ..
sinA/1+cosA=1 -cosA/sinA
sin²A =1 ² - cos²A [ by using cross multiplication rule ]
Then..
sin²A = sin²A [•° • 1 - cos²A =sin²A ]
now here LHS =RHS prooved .
hope it helps you .!!
2nd method is .
like rationalising process
so...
from LHS
sinA/1+cosA ×1 -cosA/1 - cosA
=> sinA(1+cosA)/(1 - cos²A )
=>sinA×(1+cosA)/sin²A
=>1+cosA/sinA RHS prooved .
#Rajukumar111
Given ..
sinA/1+cosA=1 -cosA/sinA
sin²A =1 ² - cos²A [ by using cross multiplication rule ]
Then..
sin²A = sin²A [•° • 1 - cos²A =sin²A ]
now here LHS =RHS prooved .
hope it helps you .!!
2nd method is .
like rationalising process
so...
from LHS
sinA/1+cosA ×1 -cosA/1 - cosA
=> sinA(1+cosA)/(1 - cos²A )
=>sinA×(1+cosA)/sin²A
=>1+cosA/sinA RHS prooved .
#Rajukumar111
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