Math, asked by Radhika411, 1 year ago

plzz ans.....Thnk u....PROVE THE FOLLOWING

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kartarkapoor2814: I will answer it tomorrow... OK then wait for tomorrow and then you have to mark my answer as brainliest.......
Radhika411: ok
kartarkapoor2814: Tomorrow promise

Answers

Answered by Anonymous
5
LHS = sec^6 A - tan^6 A

=> (sec²A)³ - (tan²A)³

=> (sec²A - tan²A) ( (sec²A)² + tan⁴A + sec²A tan²A)

=> we know that ,

sec²A = 1 + tan²A
=> sec²A - tan²A = 1


=> 1 [ ( 1+tan²A)² + tan⁴A + (1+tan²A) ( tan²A) ]

=> ( 1+tan²A )² + tan⁴A + tan²A + tan⁴A

=> 1 + tan⁴A + 2tan²A + tan⁴A + tan²A + tan⁴A

=> 1 + 3 tan⁴A + 3 tan²A

=> 1 + 3 tan²A + 3 tan⁴A


Since, LHS = RHS

=> Hence , Proved
Answered by kartarkapoor2814
0
Hope it helps you!!!! please mark it as brainliest !!! :).....:p..... :b.... :)
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