plzz ansr these questions ....
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Answers
1)Law of conservation of momentum is applicable to isolated system (no external force is applied).
In this case, the change in velocity is due to the gravitational force of earth.When the ball is thrown up, negative force of gravity is applied and so the speed becomes zero.After that due to gravitational force the ball falls down with same initial velocity.
2)According to law of conservation of linear momentum,
MV = mv.
M is mass of pistol = 2 kg.
m is mass of bullet = 2 g = 2 (10 ^-3) kg.
v = velocity of bullet = 150 m/s.
V is recoil velocity of pistol . V= (m/M) v = [ 2(10^-3)/(2)] (150) = 0.15 m/s
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