Question

plzz answer fast............​

Answer 1

Answer:

Here, ∆ABC is a right angled triangle

By Pythagoras theorem;

AC^2 = AB^2+BC^2

or, AC^2 = 4a^2+4a+1+4a^4+8a^3+4a^2

or, AC^2 = 4a^4+8a^3+8a^2+4a+1

$or \: ac = \sqrt{ {4a}^{4} + {8a}^{3} + {8a}^{2} + 4a + 1 }$

Now, when a =8;

AB = 17 units

BC = 144 units

AC =

$\sqrt{ {17}^{2} + {144}^{2} }$

Answer 2

Answer:

answer for the given problem is given