Question

plzz answer it fast plzz....urgent need​

Answer 1

Answer:

2 is correct

Step-by-step explanation:

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Answer 2

Question : 13^1001 x 7^133 x 2^143

Ans: 1st Step : we need to find the repeating units digit in 13 powers :

13^1 = 13 ( Unit Digit : 3 )                      13^5 = 371293 ( Unit Digit 3 )

13^2 = 169 ( Unit Digit : 9 )

13^3 = 2197 ( Unit Digit : 7 )

13^4 = 28561 ( Unit Digit : 1 )

So Every Four Times , The Unit Digit is repeating

2nd Step : Divide its Power with the number . which is 1001 divided by 13

1001 / 4 = 250 and remainder 1

If Remainder 1 = Unit Digit = 3

If Remainder 2 = Unit Digit = 9

If Remainder 3 = Unit Digit = 7

If Remainder 0 = Unit Digit = 1

Unit Digit = 3 for 13^1001

For 7^133

7 = unit digit 7

7*7 = unit digit 3

7*7*7 = unit digit 1

7 , 3 , 1 are repeating

If Remainder 1 = Unit Digit = 7

If Remainder 2 = Unit Digit = 3

If Remainder 0 = Unit Digit = 1

Divide 133/3 = 44 and Remanider 1

Unit Digit = 7

For 2^143

2 = unit digit 2

2*2 =  unit digit 4

2*2*2 = unit digit 8

2*2*2*2 =  unit digit 6

2,4,8,6 are repeating

If Remainder 1 = Unit Digit = 2

If Remainder 2 = Unit Digit = 4

If Remainder 3 = Unit Digit = 8

If Remainder 0 = Unit Digit = 6

143/4 = 35 and 3 remainder  = unit digit 8

Question : 3*7*8 = 168 . and unit digit 8

This is the answer i am getting

hope it helps