Question

plzz answer no. 12 in the following image wth gull explanations

Answer 1

(1) acceleration is the rate of change of velocity . here we see in V- t graph curve is straight line . it means slope of curve is same at 0 ≤ t ≤ 4 and 4 ≤ t ≤ 6 .
hence acceleration is uniform .
now,
we see in first case( 0 to 4 sec) slope of curve is positive so, uniformly acceleration
and second case ( 4sec to 6sec ) slope is negative so, uniformly deceleration .

(ii) displacement = area of ∆ = 1/2 × 6 × 2 = 6 m


(iii) no particle doesn't change the direction of motion , but particle velocity change . direction of acceleration also changes .

(iV) displacement covered in 0 ≤ t ≤ 4 = area of ∆ = 1/2 × 4 × 2 = 4 m

displacement covered in 4 ≤ t ≤ 6 = area of ∆ = 1/2 × 2 × 2 = 2 m

hence,
displacement in 0≤ t ≤ 4 = 1/2 {displacement in 4≤ t ≤ 6 }
e.g ratio = 2 : 1


( V) acceleration in 0 ≤ t ≤ 4 = ( 2 - 0)/( 4 -0) = 2/4 = 0.5 m/s²

acceleration in 4 ≤ t ≤ 6 = ( 0 - 2)/( 6 - 4) = -2/2 = - 1 m/s²

hence, retardation in 4 ≤ t ≤ 6 = 1 m/s²

Answer 2

Answer:

Hope this helps you...

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