Math, asked by deeya30, 1 year ago

plzz answer
Q 1,2&4
Answer fast​

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Answers

Answered by rrrr29
1
1)ar of triangle =1/2 (x1(y2-y3) +x2(y3-y1) +x3(y1-y2))

=1/2((-2)(3-7)+8(7-3)+6(3-3)

=1/2((-2)(-4) +8(4)+6(0)

=1/2(8+32+0)

1/2(40)

=20 unit^2

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deeya30: the answer of 2nd and 4th question is wrong edit it
rrrr29: check now and tell me
rrrr29: shuld be correct now :)
rrrr29: extremely sorry
deeya30: ya its correct now thnks
Answered by Aakanshatyagi
1
by the formula of area of triangle
1/2( -2(3-7) +8(7-3) +6(3-3) )
1/2 ( -2(-4) +8(4) +6(0)
1/2( 8+32+0)
1/2(40)
20

therefore area of triangle = 20



question 2:-
by same formula,
1/2(3(6 - 15/2) +m (15/2 - 5)+ 1/2(5-6) ) = 0
1/2(-9/2 +50m/2 -1/2 ) = 0
1/2( -9+50m - 1 /2 ) =0
50m - 5/2 =0. ( -9-1+50m = 50m+10 )
50m -5 =0
50m = 5. ( 10 is divisible by 2 )
m = 5/50
m = 1/10


question 4 :-
1/2( -3(p+5) +2(-5 -9) +4(9+5) ) =0
1/2( -3p-15 - 28 +56 ) =0
1/2( -3p+13 ) =0
-3p+13/2 =0
-3p+13 =0
p =13/3 =0





hope it will help you

deeya30: the answer of 2nd and 4th question is wrong edit it
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